2y/y^2+6y

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Solution for 2y/y^2+6y equation:


D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

6*y+(2*y)/(y^2) = 0

6*y^1+2*y^-1 = 0

(6*y^2+2*y^0)/(y^1) = 0 // * y^2

y^1*(6*y^2+2*y^0) = 0

y^1

6*y^2+2 = 0

6*y^2+2 = 0

DELTA = 0^2-(2*4*6)

DELTA = -48

DELTA < 0

y in { }

y belongs to the empty set

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